Three identical spheres, each of mass M, are placed at the comers of a right angle triangle with the mutually perpendicular sides equal to $$2$$ m (see$$ $$figure). Taking the point of intersection of the two mutually perpendicular sides as the origin, find the position vector of centre of mass. [NEET $$2020$$]

Question

Infinity Learn · Accepted Answer

The given situation as shown in the figure.                 OA $$=$$ $$2i^$$                 OB $$=$$ $$2j^Position$$ vector of centre of mass,              $$RCM=M1r1+M2r2+M3r3M1+M2+M3=M(OA)+M(OB)M+M+M$$                       $$=M$$×$$2i^+M$$×$$2j^3M=23(i^+j^)$$

Three identical spheres, each of mass M, are placed at the comers of a right angle triangle with the mutually perpendicular sides equal to 2 m (see figure). Taking the point of intersection of the two mutually perpendicular sides as the origin, find the position vector of centre of mass. [NEET 2020]

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