Questions
Three identical spheres, each of mass M, are placed at the corners of a right angle triangle with mutually perpendicular sides equal to 2 m (see figure). Taking the point of intersection of the two mutually perpendicular sides as the origin, find the position vector of centre of mass.
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Correct option is D
xcm=M×0+M×0+M×23M=23ycm=M×0+M×0+M×23M=23r→cm=23(i^+j^)
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