Questions
Three identical thin rods, each of mass m and length l, are joined to form an equilateral triangular frame. The moment of inertia of the frame about an axis parallel to its one side and passing through the opposite vertex is
detailed solution
Correct option is B
Moment of Inertia of each of rod AC and ,BC about the given axis OO' isIAC = IBC = ml23sin260° = ml24and M.I. of rod AB about the given axis OO' isIAB = m(l32)2 = 34ml2Hence,I = IAC+IBC+IAB = ml24+ml24+34ml2= 54ml2Talk to our academic expert!
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The moment of inertia of a circular disc of radius 2 m and mass 2 kg, about an axis passing through its centre of mass is 2 kg – . Its moment of inertia about an axis parallel to this axis and passing through its edge (in Kg -) is
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