Three long, straight parallel wires carrying current, are arranged as shown in figure. The force experienced by a 25 cm length of wire C is

Force on wire C due to wire D,FD= 10−7 × 2 × 30 × 103 × 10−2×25 × 10−2 = 5 × 10−4N                                                                  (Towards right)Force on wire C due to wire G,FG= 10−7 × 2 × 20 × 102 × 10−2×25 × 10−2 = 5 × 10−4N⇒   Net  force on  wire  C  is Fnet = FD −FG=0(Towards left)