First slide

Magnetic field due to a straight current carrying wire

Question

Three long, straight and parallel wires carrying currents are arranged as shown in the figure. The wire C which carries a current of5.0A is so placed that it experiences no force. The distance of wire C from wire D is x centimetre. Then x is.

Moderate

A

9 cm
B

7 cm
C

5 cm
D

3 cm

Solution

For no force on wire C, force on wire C due to wire
D = force on wire C due to wire B
$\begin{matrix} \Rightarrow \frac{μ_{0}}{4 π} \times \frac{2 \times 15 \times 5}{x} \times 1 = \frac{μ_{0}}{4 π} \times \frac{2 \times 5 \times 10}{(15 - x)} \times t \\ \Rightarrow x = 9 cm \end{matrix}$

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