Questions
Three masses of 16, 8, and 4 kg are placed in contact with each other as shown in fig. If a force of
140 N is applied on 4 kg mass, then force on 16 kg mass will be
detailed solution
Correct option is D
The common acceleration of the system will be a=Fm1+m2+m3=14016+8+4 =14028=5m/s2∴Force on16kg mass=mass×acceleration16×5=80N.Talk to our academic expert!
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