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Q.

Three masses M1, M2 and M3 are lying on a frictionless table. The masses are connected by massless threads as shown. The mass M3 is pulled by a constant force F as shown. The tension in the thread between masses M2 and M3 is

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a

M1+M2M1+M2+M3F

b

M2+M3M1+M2+M3F

c

M1+M3M1+M2+M3F

d

M1−M2M1+M2+M3F

answer is A.

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Detailed Solution

Free body diagram of masses are∴F−T1=M3a …(i)T1−T2=M2a… (ii) T2=M1a…( iii )Adding (i), (ii), and (iii) we getF=aM1+M2+M3∴a=FM1+M2+M3 …(iv)T1=M1+M2a=M1+M2F /M1+M2+M3
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