Three 2 ohm resistors are connected to form a triangle. The resistance between any two corner is
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a
6 ohm
b
2 ohm
c
(3/4) ohm
d
4/3 ohm
answer is D.
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Detailed Solution
The triangular arrangement is equivalent to a parallel combination of two ohm resistance and 4 ohm resistance (two resistances are in series). Therefore1R=12+14=2+14=34R=43ohmHence the resistance between any two corner is 4/3 ohm.