Three particles A, B and C of equal mass move with equal speed V = 5 ms-1 along the medians of an equilateral triangle as shown in the figure. They collide at the centroid G of the triangle. After the collision, A comes to rest, B retraces its path with the speed V = 5 ms-1. What is the speed of C (in ms-1)?
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answer is 5.
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Detailed Solution
Initial linear momentum vectors of the particles form a closed equilateral triangle .So vector sum of initial momentum vectors is zero .By conservation of linear momentum, momentum of the system after the collision must be zero which is possible if particle C moves along BG with speed of 5 m/s .