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Questions  

Three particles, each of mass M are moving in a circle under their mutual gravitational forces such that they always form an equilateral triangle of side a while rotating. Speed of each particle is:

a
2GMa
b
3GMa
c
GM2a
d
GMa

detailed solution

Correct option is D

2Fcos⁡60∘2=Mv2a/3where F=GM2a2So, v=GMa

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