Questions
Three particles each of mass m, are placed at the corners of an equilateral triangle of side a, as shown in Fig. The position vector of the centre of mass is
detailed solution
Correct option is A
Refer to Fig. The (x, y) co-ordinates of the masses at 0, A and B respectively are x1=0,y1=0,x2=a,y2=0,x3=a2,y3=a32Therefore, the (x, y) co-ordinates of the centre of mass are xCM=m×0+m×a+m×a/2m+m+m=a2yCM=m×0+m×0+m×a3/2m+m+m=a23∴Position vector of centre of mass is a2i^+j^3.Talk to our academic expert!
Similar Questions
Point C divides line joining A(1,2,3)m and B(2,4,-6)m in 2 : 1. If the position vector of point C is
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