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Three particles, each of mass m are placed at the vertices of a right angled triangle as shown in figure. The position vector of the centre of mass of the system is (O is the origin and are unit vectors) [EAMCET 2013]
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Correct option is D
Given, mass = mPosition of centre of mass, rCM=mai^+mbj^+m(0)k^3m⇒ rCM=13(ai^+bj^)Talk to our academic expert!
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