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Q.

Three particles, each of mass m are placed at the vertices of a right angled triangle as shown in figure. The position vector of the centre of mass of the system is (O is the origin and i^, j^, k^ are unit vectors) [EAMCET 2013]

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a

13(ai^ - bj^)

b

23(ai^ - bj^)

c

23(ai^ + bj^)

d

13(ai^ + bj^)

answer is D.

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Detailed Solution

Given, mass = mPosition of centre of mass, rCM=mai^+mbj^+m(0)k^3m⇒                                      rCM=13(ai^+bj^)
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