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Three particles, each of mass m gram, are situated at the vertices of an equilateral triangle ABC of side l cm (as shown in the figure). The moment of inertia of the system about a line AX perpendicular to AB and in the plane of ABC, in gram cm2 units will be :
detailed solution
Correct option is B
IAX=ml2+m(l/2)2+m(0)2=54ml2Talk to our academic expert!
Similar Questions
Three point masses, each of m, are placed at the corners of an equilateral triangle of side l. Then the moment of inertia of this system about an axis along one side of the triangle is
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