Three particles of equal masses are placed at the corners of an equilateral triangle as shown in the figure. Now particle A starts with a velocity $$v1$$ towards line AB, particle. B starts with a velocity $$v2$$ towards line BC and particle C starts with velocity $$v3$$ towards line CA. The displacement of CM of three particle A, B and C after time t will be (given$$ if $$v1$$ $$=$$ $$v2$$ $$=$$ $$v3)

Question

Infinity Learn · Accepted Answer

Using v→$$CM=i^vx+j^vy$$ where $$vx=mvx1+mvx2+mvx33m=0vy=mvy1+mvy2+mvy33m=0Net$$ velocity is zero (using$$ vector $$theory) i.e., CM is at rest. So, displacement of C.M. is zero. So choices (b), (c) and (d) are wrong.

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