Three particles of masses $$1$$ kg, $$2kg$$ and $$3$$ kg are situated at the corners of an equilateral triangle move at speed $$6ms$$−$$1$$,$$3ms$$−$$1$$ and $$2ms$$−$$1$$ respectively. Each particle maintains a direction towards the particle at the next corner symmetrically. Find velocity of CM of the system at this instant.

Question

Three particles of masses $$1$$ kg, $$2kg$$ and $$3$$ kg are situated at the corners of an equilateral triangle move at speed $$6ms$$−$$1$$,$$3ms$$−$$1$$ and $$2ms$$−$$1$$ respectively. Each particle maintains a direction towards the particle at the next corner symmetrically. Find velocity of CM of the system at this instant.

Infinity Learn · Accepted Answer

v→$$cm=m1v$$→$$1+m2v$$→$$2+m3v$$→$$3m1+m2+m3$$⇒ v→$$cm=$$ Total momentum  Total mass Here total momentum of system is zero,because momenfum of each particle is same in magnitude and they are symmetrically oriented as shown. So  p→$$1+p$$→$$2+p$$→$$3=0So$$, velocity of CM of the system will be zero

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Three particles of masses 1 kg, 2kg and 3 kg are situated at the corners of an equilateral triangle move at speed 6ms−1,3ms−1 and 2ms−1 respectively. Each particle maintains a direction towards the particle at the next corner symmetrically. Find velocity of CM of the system at this instant.

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