Three particles of masses 1 kg, 2kg and 3kg are situated at the corners of an equilateral triangle of side b. The coordinates of the centre of mass are (x -axis along line joining 1kg and 2kg with origin at 1 kg mass)
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a
0,7b12,33 b12
b
33b12,7b12,0
c
7b12,33 b12,0
d
7b12,0,33b12
answer is C.
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Detailed Solution
co ordinating of 3 kg =b2,3b2xcm=1×0+2b+3×b26=7b12,ycm=1×0+2×0+3×32b6=33b12zcm=1×0+2×0+3×06=0Coordinates of the center of mas = 7b12,33b12,0