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Q.

Three particles move in a straight line with initial velocities v1, v2 and v3 (v1

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a

s1=v122a,s2=v222a,s3=v322a

b

s1>s2>s3

c

s1=s2=s3

d

s1

answer is C.

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Detailed Solution

S1=v1−an−1/2O=v1−att=v1aS1=v1−av1a−1/2S2=v2−av2a−1/2S3=v3−av3a−1/2S1=S2=S3
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