First slide

Radio activity

Question

Three $α$ -particles and one $β$ -particle decaying takes place in series from an isotope ${}_{88}{Ra}^{236}$ . Finally the isotope obtained will be

NA

Solution

By using $n_{α} = \frac{A - A'}{4} and n_{β} = 2 n_{α} - Z + Z'$
$\Rightarrow A' = A - 4 n_{α} = 236 - 4 x 3 = 224 and Z' = (n_{β} - 2 n_{α} + Z) = (1 - 2 x 3 + 88) = 83$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App