Three point masses each of 1kg are placed at three corners of a square of side 2cm the gravitational field at the fourth corner of the square is (approximately)

The directions of the individual gravitational fields are as shown in the fig.Gravitational fields due to individual masses Gravitational field strength=Gmr2; universal gravitation constant=G; mass=m; distance=r; due to mass at A:  E1=G×12×10−22=1.67×10−7N/kg due to mass at C:  E2=G×12×10−22=1.67×10−7N/kg due to mass at B:  E3=G×122×10−22=0.834×10−7N/kgThe resultant of E1 and E2 acts along the diagonal in the direction of  E3Resultant of E1 and  E2, E4=E12+E22=1.67×2×10−7=2.36×10−7N/kgsay ∴Net field  E=E3+E4=0.834×10−7+2.36×10−7N/kg net Field E=3.194×10−7=3.2×10−7N/kg