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Three point masses, each of m, are placed at the corners of an equilateral triangle of side l. Then the moment of inertia of this system about an axis along one side of the triangle is

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By Expert Faculty of Sri Chaitanya
a
3ml2
b
ml2
c
34ml2
d
32ml2

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detailed solution

Correct option is C

Each angle of an equilateral triangle is 60∘⇒d=lsin⁡60∘⇒d=l32We know that the moment of inertia of a system of particles is given byI=∑i miri2⇒I=m(0)2+m(0)2+ml322⇒I=3ml24

ctaimg

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A diatomic molecule is formed by two atoms which may be treated as mass points m1 and m2,joined by a massless rod of length r. Then the moment of inertia of the molecule about an axis passing through the centre of mass and perpendicular to rod is

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