First slide

Moment of intertia

Question

Three point masses each of mass m are placed at the corners of an equilateral triangle of side b. The moment of inertia of the system about an axis coinciding with one side of the triangle is.

Moderate

A

3 m b²
B

m b²
C

(3 /4) m b²
D

(2 /3) m b²

Solution

$\begin{array}{l} M.I. = m (AD)^{2} = m {(\frac{\sqrt{3}}{2} b)}^{2} \\ = \frac{3}{4} {mb}^{2} \end{array}$

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