Three point masses, each of mass m are placed at the corners of an equilateral triangle of side l . Moment of inertia of this system about an axis along one side of triangle is
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a
3 m l2
b
32 m l2
c
m l2
d
34m l2
answer is D.
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Detailed Solution
Distance corner mass from opposite side r=l2−(l/2)2=32l I=m r2=34m l2 .