First slide

combination of resistance

Question

Three resistances of, $1 Ω$ each are connected in parallel. Such connection is again connected with $2 / 3 Ω$ resistor in series. The resultant resistance will be

Easy

A

$\frac{5}{3} Ω$
B

$\frac{3}{2} Ω$
C

$1 Ω$
D

$\frac{2}{3} Ω$

Solution

Resistance of $1 Ω$ group $= \frac{R}{n} = \frac{1}{3} Ω$
This is in series with $\frac{2}{3} Ω$ resistor.
$∴ T o t a l r e s i s \tan c e = \frac{2}{3} + \frac{1}{3} = \frac{3}{3} Ω = 1 Ω$

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