Three resistances of, 1 Ω each are connected in parallel. Such connection is again connected with 2/3 Ω resistor in series. The resultant resistance will be
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a
53 Ω
b
32 Ω
c
1 Ω
d
23 Ω
answer is C.
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Detailed Solution
Resistance of 1 Ω group = Rn=13 ΩThis is in series with 23 Ω resistor.∴ Total resistance = 23+13=33 Ω=1Ω