Three resistances of 2Ω each are connected to a 2V battery as shown in Fig. Then

The three resistances are in parallel. Their equivalent resistance is given by                      1Req=12+12+12⇒Req=23Ω∴  Current  I=2V23Ω=3ASince the resistances are in parallel, the potential difference across each resistance is the same = voltage of the battery. Further, since the three resistances are equal, the current through each is the same =I3=3A3=1A. So the correct choice is (c).