First slide

combination of resistance

Question

Three resistors each of $4 Ω$ are connected together to form a network. The equivalent resistance of the network cannot be

Moderate

A

$1.33 Ω$
B

$3.0 Ω$
C

$6.0 Ω$
D

$12.0 Ω$

Solution

If all are in series, then $R_{e q} = 12 Ω$
If all are in parallel, then $R_{eq} = \frac{4}{3} Ω = 1 .33 Ω$
If two are in series and parallel with third, then
$R_{e q} = \frac{8}{3} = 2.6 Ω$
If two are in parallel and series with third, then
$R_{e q} = 6 Ω$

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