Questions
Three rings each of mass M and radius R are arranged as shown in fig. (s). The moment of inertia of the
system about YY' will be
detailed solution
Correct option is C
The moment of inertia about Y Y'-axis is given by I=IA+IB+IC=IA+2IB ∵IB=IC =MR22+2MR22+MR2∵ ∵IB=MR22+MR2(Applying the theorem of parallel axes)=72MR2Talk to our academic expert!
Similar Questions
The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its mid-point and perpendicular to its length is I0 , Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is
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