Three rings each of mass M and radius R are arranged as shown in the figure. The moment of inertia of the system about YY' will be
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a
3MR2
b
32MR2
c
5MR2
d
72MR2
answer is D.
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Detailed Solution
MOI of system about YY′: I=I1+I2+I3where I1 = moment of inertia of ring about diameter,I2=I3=MI of inertia of ring about a tangent in a plane∴ I=12MR2+32MR2+32MR2=72MR2