Q.

Three rods of identical area of cross-section and made from the same metal form the sides of an isosceles triangle ABC, right angled at B. The points A and B are maintained at temperatures T and 2T, respectively. In the steady state, the temperature of the point C is TC. Assuming that only heat conduction takes place, TC/T is equal to

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a

1(2+1)

b

3(2+1)

c

12(2−1)

d

13(2−1)

answer is B.

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Detailed Solution

∵TB>TA⇒Heat will flow B to A via two paths(i) B to A (ii) and along BCA as shown.Rate of flow of heat in path BCA will be samei.e. QtBC=QtCA      ⇒k2T−TCAa=kTC−TA2a      ⇒TCT=31+2
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