First slide

Conduction

Question

Three rods made of the same material and having the same cross-section have been joined as shown in the figure. Each rod is of the same length. The left and right ends are kept at respectively. The temperature of the junction of the three rods will be

Easy

A

45°C
B

60°C
C

30°C
D

20°C

Solution

$\frac{Q_{1}}{t} + \frac{Q_{2}}{t} = \frac{Q}{t} \frac{KA (90 - θ)}{L} + \frac{KA (90 - θ)}{L} = \frac{KA (θ - 0)}{L} = 180 - 2 θ = θ \Rightarrow θ = 60^{\circ}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App