First slide

Conduction

Question

Three rods made of the same material and having the same cross-section have joined as shown in the Fig. Each rod is of same length. The left and right ends are kept at 0°C and 90°C respectively. The temperature of the junction of the three rods will be:

Moderate

A

45°C
B

60°C
C

30°C
D

20°C

Solution

$\frac{KA (90 - θ)}{l} + \frac{KA (90 - θ)}{l} = \frac{KA (θ - 0)}{l} \Rightarrow θ = 60^{o} C$

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