Three soap bubbles A, B and C are formed at the opened ends of a T-shaped pepe. S is a stop cock and initially it is closed. Bubbles B and C are same in size and A has the smallest radius. Then after S is opened
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
A will grow in size and size of B and C will be reduced.
b
radii of A and C will decrease and that of B will increase
c
radii of B and C will increase and finally become equal whereas the radius of A will reduce and finally become zero
d
radii of A and B will increase and finally become equal where as the radius of C will decrease and finally become zero.
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Excess pressure in a soap bubble Δp=4Tr i.e. Δp∝1r. Therefore initially Δp is maximum in A and are equal in B and C. So after S is opened, air will start flowing from A into B and C. Hence option - (3) is correct.