Three soap bubbles A, B and C are formed at the opened ends of a T-shaped pepe. S is a stop cock and initially it is closed. Bubbles B and C are same in size and A has the smallest radius. Then after S is opened

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

A will grow in size and size of B and C will be reduced.

radii of A and C will decrease and that of B will increase

radii of B and C will increase and finally become equal whereas the radius of A will reduce and finally become zero

radii of A and B will increase and finally become equal where as the radius of C will decrease and finally become zero.

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Excess pressure in a soap bubble Δp=4Tr i.e. Δp∝1r. Therefore initially Δp is maximum in A and are equal in B and C. So after S is opened, air will start flowing from A into B and C. Hence option - (3) is correct.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th