Q.
Three uniform blocks A, B and C respectively of mass m, m2 and m of different densities and dimensions are placed over each other as shown in the figure. The coefficients of friction are shown. Blocks placed in a vertical line are made to move towards right with same velocity at the same instant. Find the time (in sec) taken by the upper block A to topple from the middle block B. Assume that blocks B and C don’t stop sliding before A topples from B. (given L = 36 m, μ = 0.4 and g = 10 m/s2 )
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answer is 3.
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Detailed Solution
Since μ4<μ2<μ, the upper block will move faster than the middle block and hence force of friction on upper block is towards left ∴ f=μ4 mg∴ aA=μg4 leftwardf'=μ2(m+m2)g=34 μmg ∴ aB=μg (leftward)∴ aA/B=34 μg (rightward)For sliding down the block B, A has to move a distance 3L8Relative to block B.3L8=12 34 μgt2 ∴ t=Lμg=3 sec
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