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Q.

Three  uniform blocks  A,  B  and  C  respectively of  mass  m,  m2  and  m  of  different  densities  and  dimensions  are  placed  over  each  other  as shown  in  the  figure.  The  coefficients  of  friction  are  shown. Blocks  placed  in  a  vertical  line  are  made  to  move  towards   right with same velocity at the same instant. Find the time (in sec) taken by the upper block A to topple from the middle block B. Assume that blocks B and C don’t stop  sliding before A topples from B. (given L = 36 m,  μ = 0.4 and g = 10 m/s2 )

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answer is 3.

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Detailed Solution

Since μ4<μ2<μ, the upper block will move faster than the middle block and hence force of friction on upper block is towards left  ∴   f=μ4 mg∴   aA=μg4  leftwardf'=μ2(m+m2)g=34  μmg ∴   aB=μg  (leftward)∴   aA/B=34  μg  (rightward)For sliding down the block B, A has to move a distance  3L8Relative to block B.3L8=12  34  μgt2  ∴   t=Lμg=3  sec
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