Three uniform blocks A, B and C respectively of mass m, m2 and m of different densities and dimensions are placed over each other as shown in the figure. The coefficients of friction are shown. Blocks placed in a vertical line are made to move towards right with same velocity at the same instant. Find the time (in sec) taken by the upper block A to topple from the middle block B. Assume that blocks B and C don’t stop sliding before A topples from B. (given L = 36 m, μ = 0.4 and g = 10 m/s2 )
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is 3.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Since μ4<μ2<μ, the upper block will move faster than the middle block and hence force of friction on upper block is towards left ∴ f=μ4 mg∴ aA=μg4 leftwardf'=μ2(m+m2)g=34 μmg ∴ aB=μg (leftward)∴ aA/B=34 μg (rightward)For sliding down the block B, A has to move a distance 3L8Relative to block B.3L8=12 34 μgt2 ∴ t=Lμg=3 sec