The three vectors A→ = 3i^−2j^+k^, B→ = i^−3j^+5k^ and C→ = 2i^+j^−4k^ form
An equilateral triangle
An isosceles triangle
A right angled triangle
No triangle
A→ = 3i^−2j^+k^, B→ = i^−3j^+5k^, C→ = 2i^+j^−4k^
|A|→ = 32+(−2)2+12 = 9+4+1 = 14
|B|→ = 12+(−3)2+52 = 1+9+25 = 35
|C|→ = 22+12+(−4)2 = 4+1+16 = 21
As B = A2+C2 therefore ABC will be right angled trianlge.