The three vectors A→ $$=$$ $$3i^$$−$$2j^+k^$$, B→ $$=$$ $$i^$$−$$3j^+5k^$$ and C→ $$=$$ $$2i^+j^$$−$$4k^$$ form

Correct option is 3A right angled triangle

Questions

The three vectors $\vec{A} = 3 \hat{i} - 2 \hat{j} + \hat{k}$ , $\vec{B} = \hat{i} - 3 \hat{j} + 5 \hat{k}$ and $\vec{C} = 2 \hat{i} + \hat{j} - 4 \hat{k}$ form

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detailed solution

Correct option is C

A→ = 3i^−2j^+k^, B→ = i^−3j^+5k^, C→ = 2i^+j^−4k^|A|→ = 32+(−2)2+12 = 9+4+1 = 14|B|→ = 12+(−3)2+52 = 1+9+25 = 35|C|→ = 22+12+(−4)2 = 4+1+16 = 21As B = A2+C2 therefore ABC will be right angled trianlge.

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The three vectors A→ = 3i^−2j^+k^, B→ = i^−3j^+5k^ and C→ = 2i^+j^−4k^ form

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The three vectors $\vec{A} = 3 \hat{i} - 2 \hat{j} + \hat{k}$ , $\vec{B} = \hat{i} - 3 \hat{j} + 5 \hat{k}$ and $\vec{C} = 2 \hat{i} + \hat{j} - 4 \hat{k}$ form