First slide
Vectors
Question

The three vectors A=3i^2j^+k^B=i^3j^+5k^ and C=2i^+j^4k^ form

Moderate
Solution

A=3i^2j^+k^B=i^3j^+5k^C=2i^+j^4k^

|A|=32+(2)2+12  =  9+4+1  =  14

|B|=12+(3)2+52  =  1+9+25  =  35

|C|=22+12+(4)2  =  4+1+16  =  21

As B = A2+C2 therefore ABC will be right angled trianlge.

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