Questions
Three 60 W, 120 V light bulbs are connected across 12o V power line as shown in fig. The total power dissipated in the three bulbs is
detailed solution
Correct option is D
The resistance of each bulb is given byR=V2P=(120)260=240ΩTotal resistance of the circuitR=R+R×RR+R=240+240×240240+240=360ΩThe current in the circuiti=VR=120360=13ampTotal power produced isP=i2R=132×360=40WTalk to our academic expert!
Similar Questions
A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
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