Three waves of equal frequency having amplitudes 10 μm, 4 μm and 7 μm arrive at a given point with successive phase difference of π2. The amplitude of the resulting wave in μm is given by
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
7
b
6
c
5
d
4
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The wave 1 and 3 reach out of phase. Hence resultant phase difference between them is π.∴ Resultant amplitude of 1 and 3 = 10−7=3μmThis wave has phase difference of π2 with 4μm∴ Resultant amplitude = 32+42=5 μm