Q.

The threshold frequency for a certain metal is 3.3×1014 Hz. If light of frequency 8.2 x 1014 Hz is incident on the metal, predict the cut-off voltage for the photoelectric emission.

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a

2.0 V

b

4.04 V

c

5.04 V

d

6.04 V

answer is B.

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Detailed Solution

E=W+eVS⇒VS=hν−hν0e=hν−ν0e=4.04V
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