First slide

Photo Electric Effect

Question

The threshold frequency for a metallic surface corresponds to an energy of 6.2eV and the stopping potential for a radiation incident on this surface is 5V. The incident radiation lies in

Easy

A

ultraviolet region
B

infrared region
C

visible region
D

X- ray region

Solution

Work function W=6.2 eV
K.E_max=5eV
Energy of incident photon=W + K.Emax=11.2 eV
Wavelength of incident photon = $\frac{12400}{11.2} = 1107 A^{0}$
This lies in UV region

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