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Q.

The threshold wavelength of a metal surface is 500 nm. V is the maximum velocity of photo electrons when the wavelength of incident light is 400 nm. If the maximum velocity of photo electrons from the same metal surface is 2V, the wavelength of incident light is

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a

350 nm

b

300 nm

c

250 nm

d

200 nm

answer is C.

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Detailed Solution

12mV2=hc1λ−1λ0V1V22=1λ1−1λ01λ2−1λ0122=1400−15001λ2−15001λ2=1100−3500λ2=250 nm
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The threshold wavelength of a metal surface is 500 nm. V is the maximum velocity of photo electrons when the wavelength of incident light is 400 nm. If the maximum velocity of photo electrons from the same metal surface is 2V, the wavelength of incident light is