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Q.

The threshold wavelength of photon for a metal surface is 3640 A. If a light of wavelength 2240 A is incident on metal surface, then velocity of ejected electron will be (given h=6.63×10−34,c=3×108m/s,me=9)

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a

18.4×106 m/s

b

8.6×105 m/s

c

15×106 m/s

d

12.5×105 m/s

answer is B.

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Detailed Solution

By Einstein's photoelectric equation,12mevmax2=hc1λ−1λ0Vmax=2hcme1λ−1λ0=2×6.63×10−34×3×1089.1×10−3110102240−10103640=8.6×105 m/s
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