First slide

Force on a current carrying wire placed in a magnetic field

Question

Through two parallel wires A and B, 10 and 2 amp of currents are passed respectively in opposite directions. If the wire A is infinitely long and the length of the wire B is 2 m, the force on the conductor 8, which is situated at 10 cm distance from A, will be

Easy

A

8 x 10^-5N
B

4x10^-7N
C

4 x10^-5 N
D

$4 π \times 10^{- 7} N$

Solution

$\begin{array}{l} F = \frac{μ_{0}}{4 π} \times \frac{2 i_{1} i_{2}}{r} \times l \\ ∴ F = 10^{- 7} \times \frac{2 \times 10 \times 2}{0 \cdot 1} \times 2 \\ = 8 \times 10^{- 5} N \end{array}$

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