First slide

Force on a current carrying wire placed in a magnetic field

Question

Through two parallel wires and B, 10 and 2 ampere of currents are passed respectively in opposite direction. If the wire A is infinitely long and the length of the wire B is 2 m, the force on the conductor B, which is situated at 10 cm distance from A will be :

Moderate

A

$8 \times 10^{- 5} N$
B

$4 \times 10^{- 7} N$
C

$4 \times 10^{- 5} N$
D

$4 π \times 10^{- 7} N$

Solution

$F = \frac{μ_{0}}{4 π} \cdot \frac{2 i_{1} i_{2}}{a} \times 1 \Rightarrow F = 10^{- 7}$
$\times \frac{2 \times 10 \times 2}{(10 \times 10^{- 2})} \times 2 = 8 \times 10^{- 5} N$

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