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Q.

The time constant of a circuit is 10 sec, when a resistance of 10 Ω is connected in series in a previous circuit then time constant becomes 2 second, then the self inductance of the circuit is :

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a

2.5 H

b

5 H

c

15 H

d

25 H

answer is D.

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Detailed Solution

Time constant of LR circuit = LR = 10 …….(i)When 10 Ω is connected in seriesLR+10=2 ...........(ii)⇒R+10R=5⇒R=2.5 so L=25

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The time constant of a circuit is 10 sec, when a resistance of 10 Ω is connected in series in a previous circuit then time constant becomes 2 second, then the self inductance of the circuit is :