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Questions  

The time period and the amplitude of a simple pendulum are 4 second and 0.20 metre respectively. If the displacement is 0.1 m at time t = 0, the equation of its displacement is represented by:

a
y=0.2 sin (0.5πt)
b
y=0.2 sin (0.5πt+π/6)
c
y=0.1 sin πt+π/6
d
y=0.1 sin 0.5 πt

detailed solution

Correct option is B

y=A sin ωt+ϕIf at t=0, y=0.1 m, then                         0.1=0.2 sin ϕ⇒ϕ=π/6                             y=0.2 sin 2πt4+π6                                =0.2 sin 0.5 πt+π/6

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