Questions
The time period of a freely suspended magnet is 4 seconds. If it is broken in length into two equal parts and one part is suspended in the same way, then its time period will be
detailed solution
Correct option is B
T=2πIMBH=4 sWhen magnet is cut into two equal halves, then New magnetic moment, M'=M2New moment of inertia, I'=w/2l/2212=18.wl212Where w is the initial mass of the magnetBut, I=wl212; ∴I'=I8∴New time period T'=2πI'M'BH=2πI/8M/2BH=122πIMBH=12 x T=12 x 4=2 sTalk to our academic expert!
Similar Questions
A bar magnet is oscillating in the earth's magnetic field with a time period T. If the mass is quadrupled, then its time period will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
