The time period of a freely suspended magnet is 4 seconds. If it is broken in length into two equal parts and one part is suspended in the same way, then its time period will be

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4 s

2 s

0.5 s

0.25 s

answer is B.

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Detailed Solution

T=2πIMBH=4 sWhen magnet is cut into two equal halves, then New magnetic moment, M'=M2New moment of inertia, I'=w/2l/2212=18.wl212Where w is the initial mass of the magnetBut, I=wl212; ∴I'=I8∴New time period T'=2πI'M'BH=2πI/8M/2BH=122πIMBH=12 x T=12 x 4=2 s

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