Q.

The time period of a freely suspended magnet is 4 seconds. If it is broken in length into two equal parts and one part is suspended in the same way, then its time period will be

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

4 s

b

2 s

c

0.5 s

d

0.25 s

answer is B.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

T=2πIMBH=4 sWhen magnet is cut into two equal halves, then New magnetic moment, M'=M2New moment of inertia, I'=w/2l/2212=18.wl212Where w is the initial mass of the magnetBut, I=wl212;     ∴I'=I8∴New time period T'=2πI'M'BH=2πI/8M/2BH=122πIMBH=12 x T=12 x 4=2 s
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
whats app icon
The time period of a freely suspended magnet is 4 seconds. If it is broken in length into two equal parts and one part is suspended in the same way, then its time period will be