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Time period for a magnet is T. If it is divided in four equal parts along its axis and perpendicular to its axis as shown, then time period for each part will be

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a
4 T
b
T/4
c
T/2
d
T

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detailed solution

Correct option is C

When magnet of length l is cut into four equal parts, thenm'=m2 and l'=l2;    ∴M'=m2 x l2=ml4=M4New moment of inertiaI'=w'l'212=w4.l2212=116.wl212Here w is the mass of magnet.∴I'=116ITime period of each Part, T'=2πI'M'BH=2πI/16M/4BH=2πI4MBH=T2

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