Q.
The time period of a magnet ( when behaving like a compound pendulum) is T. The bar magnet is cut into 4 equal parts by cutting it normal to its length. The time period of each of them in the same field is
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a
T
b
T/2
c
T/4
d
2T
answer is C.
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Detailed Solution
T=2πIM.B, SoT1T2=I1I2.M2M1=641.14=41⇒T2=T14
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