The time period of a magnet ( when behaving like a compound pendulum) is T. The bar magnet is cut into 4 equal parts by cutting it normal to its length. The time period of each of them in the same field is

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T/2

T/4

answer is C.

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Detailed Solution

T=2πIM.B, SoT1T2=I1I2.M2M1=641.14=41⇒T2=T14

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