First slide

Applications of SHM

Question

The time period of a mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be

Moderate

A

T
B

$\frac{T}{2}$
C

2 T
D

$\frac{T}{4}$

Solution

By cutting spring in four equal parts force constant (K) of each parts becomes four times $(∵ k \propto \frac{1}{l})$ so by using $T = 2 π \sqrt{\frac{m}{K}};$ time period will be half i.e. $T' = T / 2$

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