First slide

Magnetic dipole in a uniform magnetic field

Question

The time period of oscillation of a magnet in vibration magnetometer is 1.5 second. The time period of oscillation of another magnet similar in size, shape and mass but having one-fourth magnetic moment than that of the first magnet oscillating at the same place will be

Moderate

A

0.75 sec
B

1.5 sec
C

3.0 sec
D

6.0 sec

Solution

$T = 2 π \sqrt{(\frac{I}{{MB}_{H}})} T = 2 π \sqrt{(\frac{I}{(M / 4) B_{H}})} = 2 [2 π \sqrt{(\frac{I}{{MB}_{H}})}]$
= 2 x 1.5 = 3sec.

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