First slide

Simple hormonic motion

Question

The time period of oscillation of a particle that executes SHM is 1.2s. The time starting from mean position at which its velocity will be half of its velocity at mean position is

Easy

A

0.1 s
B

0.2 s
C

0.4 s
D

0.6 s

Solution

$V = \frac{V_{\max}}{2} after t = \frac{T}{6} from mean position$

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