Questions
The time period of oscillation of simple pendulum is given by ; The length of the pendulum is measured as l = cm and time period as T = s. The percentage error in measuring ‘g’ is
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Correct option is A
T=2πlg g=4π2lT2Δgg=Δll+2ΔTT=0.110+2×0.020.5=0.01+0.08=0.09∆gg%=9%
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A physical quantity A is related to four observable a, b, c and d as . The percentage errors of measurement in a, b, c and d are 1 %, 3 %, 2 % and 2 % respectively. What is the percentage error in the quantity A ?
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